How to calculate H-Indexfor research publications. Author: John P Itteera.
Ex:Publication report as given by Faculty "A"
Publication year | Publication serial No. | No. of Citations. |
2001 | 1 | 15 |
2002 | 2 | 2 |
2002 | 3 | 11 |
2003 | 4 | 7 |
2004 | 5 | 7 |
2004 | 6 | 8 |
2005 | 7 | 11 |
2006 | 8 | 1 |
2007 | 9 | 4 |
2008 | 10 | 5 |
2009 | 11 | 6 |
2010 | 12 | 9 |
Total | 86 |
Now you arrange the table in descending order for the column "No. of Citations"without columns "publication year" and "Publication serial No." and add a new first column with serial number for indexing starting from 1.
1 | 15 |
2 | 11 |
3 | 11 |
4 | 9 |
5 | 8 |
6 | 7 |
7 | 7 |
8 | 6 |
9 | 5 |
10 | 4 |
11 | 2 |
12 | 1 |
Comparing "column 1" and "column 2" till "column 2" number is not lesser than "column 1" as in 7th row. Ex:-
Value in 1st row of "column 2" is greater than corresponding value in 1st row of "column 1"asvalue 15>1
Value in 2nd row of "column 2" is greater than corresponding value in 2nd row of"column 1"asvalue 11>2
Value in 3rd row of "column 2" is greater than corresponding value in 3rd row of "column 1"asvalue 11>3
Value in 4th row of "column 2" is greater than corresponding value in 4th row of "column 1" as value 9>4
Value in 5th row of "column 2" is greater than corresponding value in 5th row of"column 1" as value 8>5
Value in 6th row of "column 2" is greater than corresponding value in 6th row of "column 1" as value 7>6
Value in 7th row of "column 2" is equal to corresponding 7th row of "column 1" as value 7=7
Value in 8th row of "column 2" is less than corresponding value in 8th row of "column 1" as value 6< 8
Value in 9th row of "column 2" is less than corresponding value in 9th row of "column 1" as value 5<9
Value in 10th row of "column 2" is less than corresponding value in 10th row of "column 1" as value 4<10
Value in 11th row of "column 2" is less than corresponding value in 11th row of "column 1" as value 2< 11
Value in 12th row of "column 2" is less than corresponding value in 12th row of "column 1" as value 1< 12th
Now since value is 7th row of "column 2" is equal to corresponding value in 7th row of "column1" we consider the H-index of "A" is 7
Imagine a second scenario where value in 7th row of "column 2" is 8 and the remaining value remains same in the table, still value of H-index of "A" will remain as 7 as the value in "column 2" of subsequent row is lesser than the corresponding value in "column-1" for that row.(in this case 8)
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